10x^2-2x+12=-26x

Solution for 10x^2-2x+12=-26x equation:

10x^2-2x+12=-26x

We move all terms to the left:

10x^2-2x+12-(-26x)=0

We get rid of parentheses

10x^2-2x+26x+12=0

We add all the numbers together, and all the variables

10x^2+24x+12=0

a = 10; b = 24; c = +12;
Δ = b2-4ac
Δ = 242-4·10·12
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{6}}{2*10}=\frac{-24-4\sqrt{6}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{6}}{2*10}=\frac{-24+4\sqrt{6}}{20}
$